Question

If a pendulum swings with a period of 1.00 s and has a length of 0.250 m, calculate the magnitude of the acceleration due to gravity.

Answer 1

The magnitude of g is 9.870 m/s^2

Step-by-step explanation:

Use the formula tying the period to the length of a pendulum for small amplitudes
`T=2\pi\sqrt{(L)/(g)}\implies g = (4\pi^2 )/(T^2)L=9.870(m)/(s^2)`: