Question

In two or more complete sentences, explain how to calculate the amount of energy that is transferred when 150 g of cooper cools from 63.0 C to 21.0 C. Is the energy absorbed or released? The specific heat of copper is 0.387 J/g"c.

Answer 1

To calculate the amount of energy transferred when 150 g of copper cools from 63.0 °C to 21.0 °C, use the formula q = m ×c × ΔT, where q is the amount of energy transferred, m is the mass of the copper, c is the specific heat of copper, and ΔT is the change in temperature. The energy transferred is 2924.1 J and it is released.

Step-by-step explanation:

To calculate the amount of energy transferred when 150 g of copper cools from 63.0 °C to 21.0 °C, we can use the equation:

q = m ×c × ΔT

where q is the amount of energy transferred, m is the mass of the copper, c is the specific heat of copper, and ΔT is the change in temperature.

Given that the mass of copper is 150 g, the specific heat of copper is 0.387 J/g•°C, and the change in temperature is 63.0 °C - 21.0 °C = 42.0 °C, we can substitute these values into the equation:

q = 150 g ×0.387 J/g•°C ×42.0 °C = 2924.1 J

The energy transferred is 2924.1 J. Since the temperature of the copper decreases, the energy is released.

Answer 2

Answer: -2438.1 J and the energy is released.

Step-by-step explanation:

The amount of heat can be calculated from the relation: Q = mCΔT,

• Q is the amount of heat released or absorbed by the system.

• m is the mass of the substance (Cu) (m = 150.0 g).

• C is the specific heat capacity (C for Cu = 0.387 J/gC).
• ΔT is the temperature difference (ΔT = 21.0 - 63.0 = -42.0 °C)

• Q = (150 x 0.387 x -42) = -2438.1 J.

• The energy here is released