Answer: The correct option is
![1.11* 10^(2) g/mol](https://img.qammunity.org/2020/formulas/chemistry/high-school/3ss5l7b93kdkqh0j14bejd9bzs2ckggn57.png)
Step-by-step explanation:
Atomic mass of calcium ,Ca = 40.07 g/mol
Atomic mass of chlorine ,Cl = 35.5 g/mol
Molar mass of
:
= (Atomic mass of Ca+2 × (Atomic mass of Cl))
= (40.07 g/mol + (2 × 35.5))=111.07 g/mol
![111.07=1.1107* 10^(2) g/mol\approx 1.11* 10^(2) g/mol](https://img.qammunity.org/2020/formulas/chemistry/high-school/al8wrj6etyj19ln2qmcxyf6o4giygqco28.png)
Hence, the correct option is
![1.11* 10^(2) g/mol](https://img.qammunity.org/2020/formulas/chemistry/high-school/3ss5l7b93kdkqh0j14bejd9bzs2ckggn57.png)