130k views
2 votes
How many particles of BaCl2 reacted if 1.53 mol of it were consumed?

A) 2.54 x 10–24 particles BaCl2
B) 6.83 x 10–24 particles BaCl2
C) 3.43 x 101 particles BaCl2
D) 9.21 x 1023 particles BaCl2

User Fraxel
by
6.3k points

2 Answers

2 votes

Answer:

D = 9.21 × 1023 particles BaCl2

Step-by-step explanation:

I just took the test and got it right

User Whyceewhite
by
6.4k points
3 votes

Answer:- D)
9.21*10^2^3 particles
BaCl_2 .

Solution:- There are 1.53 moles of the compound are given and it asks to calculate the number of particles.

To calculate the number of particles we multiply the moles with Avogadro number.


1.53mol((6.022*10^2^3particles)/(1mol))

=
9.21*10^2^3

So, the D is the right choice.

User Tyler Replogle
by
6.3k points