Answer:
Given the statement: For a person standing 100 m from the center of the base of the excel tower, the angle of elevation to the top of the tower is 71.6 degrees.
Let h be the height of the Eiffel tower.
Angle of elevation is,
![\theta =71.6^(\circ)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/aow3bhm2crxx8bnake1esyxyxmpglhetrg.png)
Distance of boy standing from the center of the base of the Eiffel tower is, 100 m.
Using tangent ratio:
![\tan \theta = \frac{\text{opposite side}}{\text{Adjacent side}}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/t67ozt2ft8yrai1yuy0jpr04q6ken8uuww.png)
From the given figure as shown;
Solve for h;
![\tan 71.6 = (h)/(100)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ckk8y8vqw4jhtgnksezyud1ue0yq9sjstl.png)
Multiply both sides by 100 we have;
![h = 100 \tan 71.6](https://img.qammunity.org/2020/formulas/mathematics/middle-school/dzrqem7j31x84t40gdddvinaczqk31hc0d.png)
or
![h = 100 * 3.0061109035](https://img.qammunity.org/2020/formulas/mathematics/middle-school/pn76awsxfyqzo4i04u3c9c3k8vvhzjo8me.png)
Simplify:
![h \approx 300 m](https://img.qammunity.org/2020/formulas/mathematics/middle-school/hx2lr4hu59vv9exgttdyk4jr6zs1tsvczt.png)
therefore, the height of the Eiffel tower is, 300m