Question

How much heat would be released by 1.3 kg of water if it's temperature went from 295 k to 274 k

Answer 1

Answer: The energy released will be 114.223 kJ.

Step-by-step explanation:

To calculate the amount of heat released, we use the formula:

`Q= m* c* \Delta T`

Q = heat gained or released

m = mass of the substance = 1.3kg = 1300 g (Conversion factor: 1kg = 1000g)

c = heat capacity of water = 4.184 J/g K

`\Delta T={\text{Change in temperature}}=(274-295)K=-21K`

Putting values in above equation, we get:

`Q=1300g* 4.184J/gK* (-21)K`

Q = -114223 Joules = -114.223 kJ (Conversion Factor: 1kJ = 1000J)

Negative sign implies heat released.

Hence, heat released by 1.3 kg of water is 114.223kJ.