Question

A 25 N object requires a 5.0 N to start moving over a horizontal surface. What is the coefficient of static friction?

Answer 1

Answer: Fn= 25N

Ff= 5.0N

Ff= uFn

u= Ff/Fn

u=5.0N/25N

u= 0.2

Therefore, the coefficient of static friction is 0.2

Step-by-step explanation: Hope this was helpful

Answer 2

The coefficent of static friction is 0.20.

Explanation:

The general formula for the coefficient of static friction is = the static frictional force/the normal force. Any measurement of force is in the SI unit of Newtons (N). In this problem, we know that the normal force of the object is 25 N and that it requires a frictional force of 5 N to begin moving over a horizontal surface. When we divide the frictional force of 5 by the normal force of 25, we get an overall coefficent of static friction of 0.20.