So answer is C.
Hmm first I'll check the slanted line cutting 2nd quardrant..
some points on this line are (-3,0),(0,3),(2,5),(3,6),etc.
Testing (-3,0)=(x,y):
y=-3+3=0 (true)..comparable with y=x+3
Testing (2,5)=(x,y):
y=2+3=5 (true)..comparable with y=x+3
Since this line bounds the value within some limits less than or equal to x+3(see graph you can see it clearly)...so it can be represented by y<=x+3.
Similarly for next line cutting 1st and 4th quardrant,
Points: (0,-4),(1,-1),(2,2),etc..
Testing (0,-4)=(x,y):
y=3*0-4=-4(true)...comparable with y=3x-4
Testing (1,-1)=(x,y):
y=3*1-4=-1(true)...comparable with y=3x-4
This line bounds within the region y>3x-4
NOTE:
1)If the region is bounded by solid line(line without dot) then you write inequality as y<=something or y>= something.
2)If the region is bounded by dotted line(line withdot) then you write inequality as y<something or y> something.
Hope this helps!