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Object A attracts object B with a gravitational force of 5 newtons from a given distance. If the distance between the two objects is reduced in half, what will be the changed force of attraction between them?

A. 2.5 newtons
B. 10 newtons
C. 15 newtons
D. 20 newtons
E. 25 newtons

User Thi
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2 Answers

3 votes

Answer:

D

Step-by-step explanation:

User Yasufumi
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1 vote

Answer: option D. 20 Newtons

Step-by-step explanation:

The force of gravity acts between any two objects having mass. The magnitude of force of gravity is directly proportional to the masses (M and m) of two bodies and inversely proportional to the square of the distance (r) between them.


F=G (Mm)/(r^2)

where G is the gravitational constant.


F \propto (1)/(r^2)\\ \Rightarrow(F_1)/(F_2)=(r_2^2)/(r_1^2)\\ \Rightarrow (5 N)/(F_2)=((r_1/2)^2)/(r_1^2) \\ \Rightarrow F_2 = 20 N

Thus, if the distance between the two objects is reduced by half, the force would increase four times.

User Kodiologist
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