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The expression 1+2n(n+2) describes a pattern of numbers, where n represents a numbers position in the sequence. Write the first four terms of the sequence

User Skywind
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1 Answer

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Answer:

The first four terms of the sequence are:

7,17,31 and 49

Explanation:

The expression for the number is shown as:

i.e.
a_(n)= 1+2n(n+2)

Hence, the first four terms of the sequence are:

First term:


a_(1)=1+2* 1*(1+2)


a_(1)=1+2*3


a_(1)=7

Second Term:


a_(2)=1+2*2*(2+2)\\\\a_(2)=1+16\\\\a_(2)=17

Third Term:


a_(3)=1+2*3*(3+2)\\\\a_(3)=1+30\\\\a_(3)=31

Fourth Term:


a_(4)=1+2*4*(4+2)\\\\a_(4)=1+48\\\\a_(4)=49

Hence , the first four terms of the sequence are :


a_(1)=7


a_(2)=17


a_(3)=31


a_(4)=49

User Bukes
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