Answer:
{-7, 13}
Explanation:
|R-3| = 10
| | Distance to 0, so hypothetically |-1| = |1|
R-3 = 10 and -(R-3) = 10
R-3 = 10 R-3=-10
+3 +3 +3 +3
R=13 R=-7
|R - 3| = 10
There are two cases, one positive and one negative
R - 3 = 10 and R-3 = -10
Add 3 to each side
R - 3+3 = 10+3 and R-3+3 = -10+3
R = 13 R = -7
The solution set is {-7, 13}
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