Question

1. The solubility of AgNO3 at 20°C is 222.0g AgNO3/100g H2O. What mass of AgNO3 can be dissolved in 250 g of water at 20°C? Recall that solubility = mass of solute/ mass of solvent.

2. The solubility of methane, the major component of natural gas, in water at 20°C and 1.00 atm pressure is 0.026 g/L. If the temperature remains constant, what will be the solubility of this gas at 0.06 atm pressure? Recall the relationship between solubility and pressure for gases: S1/P1 = S2/P2

Answer 1

(1) The mass of silver nitrate is, 555 g

(2) The solubility of the gas will be, 0.433 g/L

Solution for Part 1 :

From the given data we conclude that

In 100 gram of water, the amount of silver nitrate = 222 g

In 250 gram of water, the amount of silver nitrate =
`(222)/(100)* 250=555g`

Therefore, the mass of silver nitrate is, 555 g

Solution for Part 2 :

Formula used :
`S_1P_1=S_2P_2` (at constant temperature)

where,

`S_1` = initial solubility of methane gas = 0.026 g/L

`S_2` = final solubility of methane gas

`P_1` = initial pressure of methane gas = 1 atm

`P_2` = final pressure of methane gas = 0.06 atm

Now put all the given values in the above formula, we get the solubility of methane gas.

`(0.026g/L)* (1atm)=S_2* (0.06atm)`

`S_2=0.433g/L`

Therefore, the solubility of the gas will be, 0.433 g/L