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44 votes
Find the equation of the line parallel to y = 2x - 4 that runs through the point (-2, 4).

y = 1/2x + 4

y = 2x + 8

y = 2x + 4

y = -1/2x + 8

User Stackmate
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2.9k points

2 Answers

15 votes
15 votes

Answer: y = 2x + 8

Step-by-step explanation:

This is a fairly simple problem. I hope this helps!

So, to find a line parallel, it's simple, and it only requires that for the other line to have the same slope and a different y-intercept (or same "m" and different "b" in the equation y = mx + b).

To find a line parallel to a point is slightly harder, but don't worry, I'll teach you how.

To do this, we have to recognize the point. The point given is (-2, 4) where -2 is the x-value and 4 is the y-value. Remember, points always go by (x, y).

So, we set y to 4, and we set x to -2.

When testing out lines that are parallel to a point, you must always be careful that you end up with the same value. Such as 4 = 4 or 8 = 8, etcetera.

We get:

4 = 2 × (-2) + 8

Simplifying, we get:

4 = -4 + 8

Adding -4 to 8, we get 4:

4 = 4

Thus, y = 2x + 8 is parallel to the point (-2, 4)

User Mohamed Emad Hegab
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3.1k points
22 votes
22 votes

Answer:

y = 2x + 8

Step-by-step explanation:

Equation: y = 2x - 4

Comparing it with slope intercept form "y = mx + b" where 'm' is slope and 'b' is y-intercept. This function has slope: 2 and y intercept of -4

Parallel lines has same slope.

Passes through (-2, 4)


\sf y - y_1 = m(x - x_1)


\sf y - 4 = 2(x - (-2))


\sf y - 4 = 2(x + 2)


\sf y = 2x + 4 + 4


\sf y = 2x + 8

User Andho
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3.2k points