Question

What is the solution to the system of linear equations?

{2x+4y=203x+2y=26



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Answer 1

{x = 8 , y = 1

Explanation:

Solve the following system:

{2 x + 4 y = 20 | (equation 1)

{3 x + 2 y = 26 | (equation 2)

Swap equation 1 with equation 2:

{3 x + 2 y = 26 | (equation 1)

{2 x + 4 y = 20 | (equation 2)

Subtract 2/3 × (equation 1) from equation 2:

{3 x + 2 y = 26 | (equation 1)

{0 x+(8 y)/3 = 8/3 | (equation 2)

Multiply equation 2 by 3/8:

{3 x + 2 y = 26 | (equation 1)

{0 x+y = 1 | (equation 2)

Subtract 2 × (equation 2) from equation 1:

{3 x+0 y = 24 | (equation 1)

{0 x+y = 1 | (equation 2)

Divide equation 1 by 3:

{x+0 y = 8 | (equation 1)

{0 x+y = 1 | (equation 2)

Collect results:

Answer: {x = 8 , y = 1