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Please complete this ASAP!!!!!! NEED HELP

Please complete this ASAP!!!!!! NEED HELP-example-1
User Stacee
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1 Answer

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1. Moles of 19.6 gram Aluminium

as we know that

Atomic mass of Al = 27 g/mol


n_(Al) = (19.6)/(27) = 0.725

2. moles of 15.7 g Nitrogen

as we know that

Atomic mass of nitrogen = 28 g/mol


n = (15.7)/(28) = 0.56

3. moles of 15.9 g Water

as we know that

Atomic mass of water = 2 + 16 = 18 g/mol


n = (15.9)/(18) = 0.88

4. moles of 10 g Ammonia

as we know that

Atomic mass of Ammonia = 14+ 3 = 17 g/mol


n = (10)/(17) = 0.588

5. moles of 14.2 g Ammonium Phosphate

as we know that

Atomic mass of Ammonium Phosphate = 14(3) + 31 + 16(4) = 137 g/mol


n = (14.2)/(137) = 0.104

User Don Gilbert
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