Question

Given the following chemical reaction: 2 O2 + CH4 CO2 + 2 H2O What mass of CO2 is produced in the reaction of 4 moles of CH4 in excess O2? 6 C 12.01 Carbon 1 H 1.01 Hydrogen 8 O 16.00 Oxygen A. 44 grams B. 64 grams C. 164 grams D. 176 grams

Answer 1

Answer: D. 176 grams

Explanation:

`2O_2+CH_4\rightarrow CO_2+2H_2O`

As methane is a limiting reagent as it limits the formation of product and oxygen is the excess reagent as it is in excess.

According to the given balanced equation,

1 mole of methane produces 1 mole of
`CO_2`

Thus 4 moles of methane will produce 4 moles of
`CO_2`

Mass of
`CO_2={\text {no of moles}}* {\text {Molar mass}}`

Mass of
`CO_2=4* 44g/mol= 176g`

Thus 176 g of
`CO_2` is produced in the reaction of 4 moles of
`CH_4` in excess
`O_2`.