Question

The angle of elevation of the sun (the angle the rays of sunlight make with the flat ground) at 10:00 a.m. is 29°. At that point, a tree’s shadow is 32 feet long. How tall is the tree?

Answer 1

Height of the tree is approx 17.74 feet.

Explanation:

the angle of elevation of the sun at 10:00 a.m. is 29°.

Then measure of angle C = 29°

At that point, a tree’s shadow is 32 feet long.

Then BC=32

Now we need to find about how tall is the tree.

So we can use trigonometric formula of right triangle to find missing height (x) of side AB.

`\tan\left(C\right)=(AB)/(BC)`

`\tan\left(29^o\right)=(x)/(32)`

`\tan\left(29^o\right)=(x)/(32)`

`0.55431=(x)/(32)`

`0.55431*32=x`

`17.73792=x`

Hence height of the tree is approx 17.74 feet.