Question

What is the polynomial function of lowest degree with lead coefficient 1 and roots i, –2, and 2?

Answer 1

Answer:b.f(x) = x^4 – 3x^2 – 4

Explanation:

Answer 2

x^4 - 3x^2 - 4.

Explanation:

Imaginary roots occur as conjugate pairs so a 4th roots is -i.

So in factor form we have:

f(x) = (x - 2)(x + 2)(x - i)x + i)

= (x^2 + 1)(x - 2)(x + 2)

= (x^2 + 1)(x^2 - 4)

= x^4 - 3x^2 - 4.