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How do you factor x^2+8x-5=4?

1 Answer

1 vote

Answer:

(x + 9)(x - 1)

Explanation:

First, set the equation equal to zero by subtracting 4 from both sides:

x² + 8x - 5 = 4

x² + 8x - 9 = 0

Then, find two factors of -9 that add to 8.

These factors are the numbers 9 and -1.

Then, using these factors, put the equation in factored form:

x² + 8x - 9 = 0

(x + 9)(x - 1) is the factored equation

User Ameera
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