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The domain of y=log(9-x^2),xER, is

User Bob Meliev
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1 Answer

4 votes

Explanation:

log(z) is defined when z > 0.

For log(9 - x²) to be defined, we have 9 - x² > 0.

=> x² < 9, -3 < x < 3.

The domain of y = log(9 - x²) is (-3,3).

User Latika Agarwal
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