Question

Trigonometry Problem Solving

Two farmhouses A and B are 10.3km apart. A third farmhouse C is located such that angle A=83 degrees, and angle B=59 degrees. How far is C from A?

Answer 1

Explanation:

Angle C = 180° - 83° - 59° = 38°

By Sine rule,

AC/sinB = AB/sinC

Therefore AC = ABsinB/sinC

= 10.3sin59°/sin38°

= 14.34km.