Question

A bus start from rest. If the acceleration of bus is 0.5 m/s square. what will be its velocity at the end of 2 minutes?what will be the distance cover?​

Answer 1

`\fbox {Velocity = 60 m/s, Distance = 3600 m}`

Step-by-step explanation:

Part (i) : Velocity at end of 2 minutes

Equation used ⇒
`\boxed {v = u + at}`

⇒ t = 2 minutes = 2 x 60 = 120 seconds

⇒ v = 0 + (0.5)(120)

⇒ v = 60 m/s

Part (ii) : Distance covered

Equation used ⇒
`\boxed {S = (v^(2)-u^(2))/(2a)}`

⇒ S = (60)² - (0)² / 2(0.5)

⇒ S = 3600 m

Answer 2

3586

Step-by-step explanation:

by using formula s=it+0.5at^2