Answer:
4.81 L
Step-by-step explanation:
From the question given above, we obtained the following information:
Initial temperature (T₁) = 298 K
Initial Volume (V₁) = 6 L
Final Temperature (T₂) = – 34 °C
Final Volume (V₂) =?
Next, we shall convert – 34 °C to Kelvin temperature. This can be obtained as follow:
T(K) = T(°C) + 273
T(°C) = – 34 °C
T(K) = – 34 + 273
T(K) = 239 K
Thus, –34 °C is equivalent to 239 K
Finally, we shall determine the final volume of the balloon as follow:
Initial temperature (T₁) = 298 K
Initial Volume (V₁) = 6 L
Final Temperature (T₂) = 239 K
Final Volume (V₂) =?
V₁ / T₁ = V₂ / T₂
6 / 298 = V₂ / 239
Cross multiply
298 × V₂ = 6 × 239
298 × V₂ = 1434
Divide both side by 298
V₂ = 1434 / 298
V₂ = 4.81 L
Thus, the volume of the balloon when it was brought outside the store was 4.81 L.