Question

A potter's wheel rotating at 215 rev/min is switched off and rotates through 75.0 revolutions prior to coming to rest. What is the constant angular acceleration of the potter's wheel during this interval

Answer 1

Step-by-step explanation:

Given :

Initial angular velocity =w_i= 215 rev/min

Final angular velocity =w_f= 0

Number of revolutions=n =75.0 rev

Using relation

`w_f^2-w_i^2=2\alpha n`

`0-215^2=2* 75\alpha`

`-308.1666 rev/min^2=\alpha`

Converting to rad/s^2

`\alpha =-1.45 rad/s^2`