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Two +1 C charges are separated by 30000 m, what is the magnitude of
the force?

User Parapote
by
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1 Answer

2 votes

Answer:

The magnitude of the force is 10 N

Step-by-step explanation:

Coulomb's Law

The electrostatic force between two charged objects is directly proportional to the product of their charges and inversely proportional to the square of the distance between the two objects.

Written as a formula:


\displaystyle F=k(q_1q_2)/(d^2)

Where:


k=9\cdot 10^9\ N.m^2/c^2

q1, q2 = the objects' charge

d= The distance between the objects

We have two identical charges of q1=q2=1 c separated by d=30000 m, thus the magnitude of the force is:


\displaystyle F=9\cdot 10^9(1*1)/(30000^2)


\displaystyle F=9\cdot 10^9(1*1)/(30000^2)

F = 10 N

The magnitude of the force is 10 N

User Rkrahl
by
4.8k points