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What is the value of a if a equals to axaxa=a+a+a

1 Answer

6 votes

Answer:


\huge\boxed{a=0\ \vee\ a=-\sqrt3\ \vee\ a=\sqrt3}

Explanation:


a\cdot a\cdot a=a+a+a\\\\a^3=3a\qquad|\text{subtract } 3a\ \text{from both sides}\\\\a^3-3a=0\qquad|\text{distribute}\\\\a(a^2-3)=0\iff a=0\ \vee\ a^2-3=0\\\\a=0\ \vee\ a^2=3\\\\a=0\ \vee\ a=-\sqrt3\ \vee\ a=\sqrt3

User Meirav
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