Question

a 15 kg block of substance with specific heat capacity 840J/kg is heated by 15 c.assume its volume change to be negligible by how much its internal energy increases​

Answer 1

Q = 189000 [J]

Step-by-step explanation:

The internal energy or heat can be calculated by means of the following expression.

`Q=m*c_(p)*DT`

where:

Q = internal energy or heat [J]

m = mass = 15 [kg]

Cp = 840 [J/kg*°C]

DT = temperature change = 15 [°C]

`Q = 15*840*15\\Q = 189000 [J]`