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Pls help, I've been stuck on this for a week

Using the Pythagorean identity, sin^2C + cos^2C = 1, solve for sinC.

User Aogan
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1 Answer

3 votes

Answer:


\sin(C)=\pm√(1-\cos^2(C))

Explanation:

Given the Pythagorean Identity:


\sin^2(C)+\cos^2(C)=1\\

We want to solve for sin(C).

First, we will subtract cos²(C) from both sides:


\sin^2(C)=1-\cos^2(C)

Next, we will take the square root of both sides. Since we are taking an even-root, we will need to add plus/minus. Hence:


\sin(C)=\pm√(1-\cos^2(C))

User Dmitrii Semikin
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