Question

Pls help, I've been stuck on this for a week

Using the Pythagorean identity, sin^2C + cos^2C = 1, solve for sinC.

Answer 1

`\sin(C)=\pm√(1-\cos^2(C))`

Explanation:

Given the Pythagorean Identity:

`\sin^2(C)+\cos^2(C)=1\\`

We want to solve for sin(C).

First, we will subtract cos²(C) from both sides:

`\sin^2(C)=1-\cos^2(C)`

Next, we will take the square root of both sides. Since we are taking an even-root, we will need to add plus/minus. Hence:

`\sin(C)=\pm√(1-\cos^2(C))`