Answer:
Please check the complete explanation below.
Explanation:
We know that the slope-intercept form of the line equation
where m is the slope and b is the y-intercept
ANALYZING TABLE 1
Part A)
Given table 1
x 0 1 2 3
y 1 3 5 7
From table 1, the y-intercept can be determined by setting x=0 and checking the corresponding y-value.
so at x = 0, y = 1
Thus, the y-intercept is (0, 1).
From the graph, it is clear that the line W has a y-intercept (0, 1).
Therefore, table 1 represents the line W.
Part B)
Taking two points (0, 1) and (1, 3) to find the slope using the formula
m = (y₂-y₁) / (x₂-x₁)
m = 3-1 / 1-0 = 2/1 = 2
now substituting m = 2, and b = 1 in the slope-intercept form
y = mx+b
y = 2x+1
Thus, table 1 represents the line W with the equation line y = 2x+1
ANALYZING TABLE 2
Part A)
Given table 2
x 0 1 2 3
y 0 3 6 9
From table 2, the y-intercept can be determined by setting x=0 and checking the corresponding y-value.
so at x = 0, y = 0
Thus, the y-intercept (0, 0).
From the graph, it is clear that line F has a y-intercept (0, 0).
Therefore, table 2 represents the line F.
Part B)
Taking two points (0, 0) and (1, 3) to find the slope using the formula
m = (y₂-y₁) / (x₂-x₁)
m = 3-0 / 1-0 = 3/1 = 3
now substituting m = 3, and b = 0 in the slope-intercept form
y = mx+b
y = 3x+0
y = 3x
Thus, table 2 represents the line F with the equation y = 3x
ANALYZING TABLE 3
Part A)
Given table 1
x 0 1 2 3
y 2 3 4 5
From table 3, the y-intercept can be determined by setting x=0 and checking the corresponding y-value.
so at x = 0, y = 0
Thus, the y-intercept (0, 2).
From the graph, it is clear that line N has a y-intercept (0, 2).
Therefore, table 3 represents line N.
Part B)
Taking two points (0, 2) and (1, 3) to find the slope using the formula
m = (y₂-y₁) / (x₂-x₁)
m = 3-2 / 1-0 = 1/1 = 1
now substituting m = 1, and b = 2 in the slope-intercept form
y = mx+b
y = (1)x+2
y = x+2
Thus, table 2 represents the line N with the equation y = x+2