Question

Help pleaseeeeeeeeeeeeeeeeeee

Answer 1

`Area = 98.2142857143`

`Perimeter = 39.2857142857`

Explanation:

From the attachment, we have:

• 2 semicircles B and C
• 1 quarter circle CDE
• radius, r = 5cm

To calculate the total area of the figure, we have to calculate the areas of individual shapes, then add them together

For Semicircle B

`Area = (\pi r^2)/(2)`

Substitute 5 for radius (r)

`A_1 = (\pi * 5^2)/(2)`

`A_1 = (\pi * 25)/(2)`

`A_1 = (25\pi)/(2)`

For Semicircle C

`Area = (\pi r^2)/(2)`

Substitute 5 for radius (r)

`A_2= (\pi * 5^2)/(2)`

`A_2 = (\pi * 25)/(2)`

`A_2 = (25\pi)/(2)`

For Quarter circle DC

`Area = (\pi r^2)/(4)`

Substitute 5 for radius (r)

`A_3= (\pi * 5^2)/(4)`

`A_3= (\pi * 25)/(4)`

`A_3= (25\pi)/(4)`

The area of the shape is:

`Area = A_1 + A_2 +A_3`

`Area = (25\pi)/(2)+(25\pi)/(2)+(25\pi)/(4)`

Take LCM

`Area = (50\pi+50\pi+25\pi)/(4)`

`Area = (125\pi)/(4)`

Take

`\pi = (22)/(7)`

So, we have:

`Area = (125)/(4) * (22)/(7)`

`Area = (125*22)/(4*7)`

`Area = (2750)/(28)`

`Area = 98.2142857143`

To calculate the total perimeter of the figure, we have to calculate the circumference of individual shapes, then add them together

For Semicircle B

`Circumference = \pi r`

Substitute 5 for radius (r)

`C_1 = \pi * 5`

`C_1 = 5\pi`

For Semicircle C

`Circumference = \pi r`

Substitute 5 for radius (r)

`C_2 = \pi * 5`

`C_2 = 5\pi`

For Quarter circle DE

`Circumference = (\pi r)/(2)`

Substitute 5 for radius (r)

`C_3 = (\pi * 5)/(2)`

`C_3 = (5\pi)/(2)`

The perimeter of the shape is:

`Perimeter = C_1 + C_2 + C_3`

`Perimeter = 5\pi + 5\pi + (5\pi)/(2)`

Take LCM

`Perimeter = (10\pi + 10\pi + 5\pi)/(2)`

`Perimeter = (25\pi)/(2)`

Take

`\pi = (22)/(7)`

So, we have:

`Perimeter = (25)/(2) * (22)/(7)`

`Perimeter = (25*22)/(2*7)`

`Perimeter = (550)/(14)`

`Perimeter = 39.2857142857`