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The lines represented by the equations 15y + 10x = -60 and y

- x – 5 are
neither parallel nor perpendicular
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parallel
perpendicular
the same line

User Dlofrodloh
by
7.2k points

1 Answer

4 votes

Final answer:

The lines represented by the given equations are neither parallel nor perpendicular.

Step-by-step explanation:

To determine the relationship between the lines, we need to compare their slopes.

1. Rewrite the equations in slope-intercept form (y = mx + b):

Equation 1: 15y + 10x = -60

15y = -10x - 60

y = -(2/3)x - 4

Equation 2: y - x = 5

y = x + 5

2. Compare the slopes:

The slope of Equation 1 is -2/3.

The slope of Equation 2 is 1.

3. Analyze the relationship:

Not parallel: Parallel lines have the same slope. These lines have different slopes, so they are not parallel.

Not perpendicular: Perpendicular lines have slopes that are negative reciprocals of each other. The negative reciprocal of -2/3 is 3/2, which is not the slope of Equation 2.

Therefore, the lines are not perpendicular.

Not the same line: The lines have different y-intercepts (-4 and 5), so they cannot be the same line.

Conclusion: The lines represented by the given equations are neither parallel nor perpendicular.

User Alexei Artsimovich
by
7.3k points
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