Question

Samuel found the difference of the polynomials. (15x^2+11y^2+8x)-(7x^2+5y^2+2x)= blankx^2+6y^2+6x What value is missing from his solution?

Answer 1

Co-efficient of
`x^(2)` is missing.

It should be 8
`x^(2)`.

Explanation:

Given two polynomials:

1st polynomial:
`15x^2+11y^2+8x`

2nd polynomial:
`-7x^2+5y^2+2x`

To find:

The value in the blank:

`(15x^2+11y^2+8x)-(7x^2+5y^2+2x)= \_\_ \ x^2+6y^2+6x`

Solution:

Here, we have 3 pair of like terms.

2 terms with
`x^(2)`, 2 terms with
`y^(2)`and 2 terms with
`x`.

Like terms can be subtracted.

Subtracting the terms with
`y^(2)`, the coefficients will get subtracted.

`11y^2 - 5y^2 = 6y^2`

Subtracting the terms with
`x`, the coefficients will get subtracted.

`8x -2x=6x`

Subtracting the terms with
`x^(2)`, the coefficients will get subtracted.

`15x^2 - 7x^2 =\bold{8}x^2`

Therefore, the answer is:

Co-efficient of
`x^(2)` is missing.

It should be 8
`x^(2)`.