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Sin^2a-sin^2b=cos^2b-cos^2a​
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Sin^2a-sin^2b=cos^2b-cos^2a​

User Justin Buser
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1 Answer

1 vote

Answer:

see explanation

Explanation:

Using the trigonometric identity

sin²x + cos²x = 1 , then sin²x = 1 - cos²x

Consider the left side

sin²a - sin²b

= (1 - cos²a) - (1 - cos²b)

= 1 - cos²a - 1 + cos²b

= cos²b - cos²a

= right side , thus verified

User ChrisC
by
8.6k points
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