Note: You missed to add some basic information of the perpendicular line or missed the answer options, hence I am solving using a sample equation but it would clear your concept.
Answer:
Please check the attached graph.
Explanation:
We know the slope-intercept form of line equation is
![y = mx+b](https://img.qammunity.org/2021/formulas/mathematics/high-school/65dxh1fg3jfjanwatlvuvqa4t096a6as1k.png)
where m is the slope and b is the y-intercept
Given the points
Finding the slope between F(1, 8) and G(-3, -4)
![\mathrm{Slope}=(y_2-y_1)/(x_2-x_1)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/nrlo6m8wdo12tyt9h1mdgp9vd4866t2plg.png)
![\left(x_1,\:y_1\right)=\left(1,\:8\right),\:\left(x_2,\:y_2\right)=\left(-3,\:-4\right)](https://img.qammunity.org/2021/formulas/mathematics/high-school/w8eziey1jet8h8m55b64n9h48zgru7grqm.png)
![m=(-4-8)/(-3-1)](https://img.qammunity.org/2021/formulas/mathematics/high-school/n4yrv0bxy5yt6wh73shx9633qwy1g3fe3f.png)
![m=3](https://img.qammunity.org/2021/formulas/mathematics/middle-school/1gd7netuxdn1rni2nn5jlsja6h6py5j1k1.png)
Thus, the slope of the line FG = m = 3
From the given line, we can also determine the y-intercept 'b' by setting x = 0 and checking the corresponding y value.
i.e. at x = 0, y = 5
Thus, y-intercept b = 5
so substituting m = 3 and b = 5 in the slope-intercept form
y = mx+b
y = 3x+5
Therefore, the equation of line FG will be:
Please check the attached diagram, where the red line represents the line y=3x+5
We know that a line perpendicular to another line contains a slope that is the negative reciprocal of the slope of the other line.
Slope of Perpendicular line = -1/m = -1/3
Thus, any line with the slope m = -1/3 would be the line that will be perpendicular to line FG
Let say the line with the slope m = -1/3 and y-intercept 2
y = -1/3x + 5
Please check the attached graph, the blue line is representing the perpendicular line y = -1/3x + 5 to line FG
The graph of both lines is clearly representing that the line y = -1/3x + 5 is perpendicular to line FG.