Question

Can someone please help???

Answer 1

Proof (reasons are given in brackets):

Consider
`\triangle ABC`,
`\triangle EDC`:

`\overline B \overline C = \overline D \overline C` (given)

`\angle BCA = \angle DCE` (vertically opposite angles are equal)

`\overline A \overline C = \overline E \overline C` (given)

`\therefore \triangle ABC \cong \triangle EDC` (SAS)

Hope this helps :)