Question

a car initially traveling at 5 m/s accelerates for 2 seconds at 3 m/s. how far does it travel during this time?

Answer 1

x = 16 [m]

Step-by-step explanation:

This problem can be solved using the following equation of kinematics.

`v_(f)=v_(o)+a*t`

where:

Vf = final velocity [m/s]

Vo = initial velocity = 5 [m/s]

a = acceleration = 3 [m/s²]

t = time = 2 [s]

`v_(f)=5+3*(2)\\v_(f)=11[m/s]`

Now we can find the displacement using the following equation of kinematics.

`v_(f)^(2) =v_(o)^(2) +2*a*x\\11^(2)=5^(2) +2*3*x\\96=6*x\\x=16[m]`