Question

City worker drain a community pool that contains 403,920 gallons of water. The pump they use removes water at a rate of 40 cubic feet per minute. One cubic foot of water contains 7.48 gallons how long in hours will it take to remove all the water from the pool

Answer 1

It will take approximately 22.52 hours to remove all the water from the pool using a pump that removes water at a rate of 40 cubic feet per minute.

Step-by-step explanation:

To find the time it will take to remove all the water from the pool, we need to convert the volume of the pool to cubic feet. We can do this by dividing the volume of the pool in gallons by the number of gallons in a cubic foot. So, 403,920 gallons / 7.48 gallons per cubic foot = 54,036.8 cubic feet.

Next, we can divide the volume of the pool in cubic feet by the rate at which the pump removes water, which is 40 cubic feet per minute. So, 54,036.8 cubic feet / 40 cubic feet per minute = 1350.92 minutes.

Finally, to convert minutes to hours, we divide by 60. 1350.92 minutes / 60 minutes per hour = 22.52 hours.

Answer 2

22.5 hours

Step-by-step explanation:

One cubic foot of water contains 7.48 gallons, so 40 cubic feet of water would equal 7.48 × 40, or 299.2 gallons. So the pumping rate is 299.2 gallons per minute. Multiplying 299.2 by 60, we have

299.2 × 60, or 17952 gallons per hour. Finally, divide 403,920 by 17,952 to find the number of hours to remove all the water: 403,920 ÷ 17,952 = 22.5 hours