Question

Someone help me as fast as possible!!

Answer 1

`\quad \huge \quad \quad \boxed{ \tt \:Answer }`

`\qquad \tt \rightarrow \: length = 11 \: \: in`

`\qquad \tt \rightarrow \: width = 4 \: \: in`

____________________________________

`\large \tt Solution \: :`

Let the measures be :

• width = x

• length = x + 7

`\textsf{\large Area of rectangle :}`

`\qquad \tt \rightarrow \: Area = length \sdot width`

`\qquad \tt \rightarrow \: 44 = x \sdot(x + 7)`

`\qquad \tt \rightarrow \: {x}^(2) + 7x = 44`

`\qquad \tt \rightarrow \: {x}^(2) + 7x - 44 = 0`

`\qquad \tt \rightarrow \: {x}^(2) + 11x - 4x - 44 = 0`

`\qquad \tt \rightarrow \: x(x + 11) - 4(x + 11) = 0`

`\qquad \tt \rightarrow \: (x + 11)(x - 4) = 0`

possible values of x = -11 and 4

`\textsf{But the acceptable value of x = 4}`

[ length or width of rectangle can't be negative ]

`\qquad \tt \rightarrow \: length = x + 7 = 4 + 7 = 11 \: \: in`

`\qquad \tt \rightarrow \: width = x = 4 \: \: in`

Answered by : ❝ AǫᴜᴀWɪᴢ ❞