Question

Limit b⇒0 (Sin b)/b³

Answer 1

infinity

Explanation:

Given the function

Limit b⇒0 (Sin b)/b³

First substitute the value of b into the function to have

Limit b⇒0 (Sin b)/b³

= sin 0/0³

= 0/0 (Ind)

Apply lhospital rule

Limit b⇒0 (d./db(Sin b))/(d/db(b³))

=>Limit b⇒0 (cos b)/3b²

Substitute the value of b

Cos 0/3(0)²

= 1/0

= infinity

Hence the answer is infinity