Question

1. A rocket is launched straight up into the air. If its entire flight takes 5 seconds....

A) What is the initial velocity of the rocket?
Om/s
B) What is the maximum height the rocket reaches?

Answer 1

1)49m/s

2)122.5m

Step-by-step explanation:

The expression below can be use to calculate the initial velocity from law of motion

V2 - V1= at

Where V2= final velocity

V1= initial velocity( from rest)

a=acceleration

t= time= 5 seconds

But V2=0

V1=gt

Where g= acceleration due to gravity= 9.8m/s^2

V1= 9.8×5

V1=49m/s

Then we can now calculate the maximum height the rocket reaches by using below formula

V^2=2gh

h(max)=v^2/2g

Where h= maximum height

V2= initial velocity

=49^2/(2×9.8)

=2401/19.6

=122.5m

Hence the maximum height it reaches vis 122.5m