Answer:
The roots are real and equal then the discriminant must be zero
So b²-4ac = 0
=>K²-4(1)(k+3)= 0
=> K²-4k-12 = 0
=> K2-6k+2k-12 = 0
=>K(K-6)+2(k-6)= 0
=>(K-6)(k+2) = 0
K = 6 or -2
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