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Which expression is a factor of 21 x2 + 13 x-20

User Penu
by
7.1k points

2 Answers

7 votes

Answer:

(7x−5)(3x+4)

Explanation:

Step-1 : Multiply the coefficient of the first term by the constant -21 • 20 = -420

Step-2 : Find two factors of -420 whose sum equals the coefficient of the middle term, which is 13 .

-420 + 1 = -419

-210 + 2 = -208

-140 + 3 = -137

-105 + 4 = -101

-84 + 5 = -79

-70 + 6 = -64

-60 + 7 = -53

-42 + 10 = -32

-35 + 12 = -23

-30 + 14 = -16

-28 + 15 = -13

-21 + 20 = -1

-20 + 21 = 1

-15 + 28 = 13 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -15 and 28

-21x2 - 15x + 28x + 20

Step-4 : Add up the first 2 terms, pulling out like factors :

-3x • (7x+5)

Add up the last 2 terms, pulling out common factors :

4 • (7x+5)

Step-5 : Add up the four terms of step 4 :

(-3x+4) • (7x+5)

User Guillaumepotier
by
7.3k points
5 votes

Answer:

(7x−5)(3x+4)

Explanation:

I think this is the answer

User Wasker
by
7.7k points