Question

Two hot air balloons are traveling along the same path from a town beginning from different locations at the same time. Henry balloon begins 15 miles from the town and is 31 miles from town after 2 hours. The distance of Tasha's balloon from the town is represented by the function y equals 5x + 25. Which plan was farther from the town at the beginning in which travel more quickly

Answer 1

Henry's balloon was farther from town at first, but Tasha's balloon traveled more quickly.

Explanation:

Answer 2

The balloon that was farther from the town at the beginning and the one which traveled more quickly is as follows;

C. Tasha's balloon was farther from the town at the beginning but Henry's balloon traveled more quickly.

What balloon was faster?

The following is how we can determine whose balloon was faster at the beginning and the one that moved more quickly;

For Henry,

x = 0 miles

y = 15 miles

x = 2 hours, y = 31 miles

For Tasha,

y = 5x + 25

At the beginning, x = 0

Substituting 0 in the above equation gives;

y = 5(0) + 25

y = 25 miles at the start

After 2 hours;

y = 5(2) + 25

y = 35 miles

Henry's speed was 12 miles per hour while Tasha's speed was 6 miles per hour.

So, Tasha's balloon was farther from the town at the beginning but Henry's balloon traveled more quickly.