Question

The theoretical yield of silver was

determined at 241 g Ag through
calculation. Instead, the reaction
generated only 192 g Ag. What is the percent yield of the reaction?

2AgNO3 + Zn → 2Ag + Zn(NO3)2

[?] %

Answer 1

79.7%

Step-by-step explanation:

Percentage yield = (actual yield/theoretical yield)*100%

Therefore percentage yield for this experiment is:
`(192)/(241) *100%`%

`= 0.79668*100`%

Percentage yield = 79.668%

Rounded to 3 significant figures is 79.7%

Hope this helped!