Question

It requires 2,500 joules to raise a certain amount of water (c = 4.186 j/g°c) from 20.0°c to 60.0°c. what is the mass of the water that is being heated? 15 g 40 g 63 g 80 g

Answer 1

Answer: B (15g)

Step-by-step explanation:

Answer 2

15 grams of water will absorb 2,500 Joules in going from 20.0 to 60.0 C.

Step-by-step explanation:

The heat involved in raising a mass (m) of a substance with a specific heat (c) from one temperature to another (Delta T) is given by:

Heat = mc(Delta T)

2,500 Joules = m*(4.186J/gC)*(60C-20C)

2,500 Joules = m*(4.186J/gC)*(40C)

2,500 Joules = m*(4.186J/gC)*(40C)

m = (2,500J)/(4.186*40J/g)

m = 14.93 grams