Question

Need help with this ASAP if you could that would help!!

Answer 1

the distance between DE is 2

The distance of EF is 5

The distance of FD is
`√(29)`

Perimeter is 7+
`√(29)`

Explanation:

Distance of DE

`√((-3-(-3))^2+(3-1)^2)`

sqrt(
`(-3+3)^2+(2)^2`)

sqrt(
`(0)^2+4`)

`√(4)`

=2

Distance of EF

`√((2-(-3))^2+(3-3)^2)`

Solve that like DE and it equals 5

Distance of FD

`√((2-(-3))^2+(3-1)^2)`

equals to
`√(29)`

P=DE+EF+FD

P=2+5+
`√(29)` = 7+
`√(29)`