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What is the equation of the line perpendicular to y=1/3x-8 through (-1,4)?

What is the equation of the line perpendicular to y=1/3x-8 through (-1,4)?-example-1

1 Answer

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Answer:

3x + y = 1

Explanation:

The line that is perpendicular to y = 1/3x - 8 would have the negative reciprocal as the slope. So this means that the equation for the perpendicular line would be y = -3x + b. To find b, you can replace x and y with the coordinates from the point given (-1, 4). The equation would be 4 = -3(-1) +b. After solving this, you get 4 = 3 + b. Subtract 3 from both sides to isolate b, and you will get b = 1. When you plug this into the original equation, you get

y = -3x + 1. When put in standard form, you get 3x + y = 1.

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