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5 votes
Write the equation of the line parallel to
y=-2/3x+4 and through the point (–3, 15)

2 Answers

4 votes

Answer:

y=-2/3x+17

Explanation:

y=-2/3x+4

slope of that line is -2/3

y-y1=m(x-x1)

(-3,15)

y-15=-2/3(x-(-3))

y-15=-2/3x+2

y=-2/3x+17

User Klappvisor
by
8.0k points
4 votes
Parallel = same slope
y = -2/3x + b
Plug in point
15 = -2/3(-3) + b
15 = 2 + b, b = 13
Solution: y = -2/3x + 13
User Pate
by
8.7k points