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A ball is thrown from the top row of seats in a stadium. The function h(t)=-16t2+48t+160 gives the height, t, in feet, of the ball t seconds after it is thrown. How long will it be before the ball hits the ground?

User Slabgorb
by
6.9k points

1 Answer

2 votes

Answer:

t = 5 s

Explanation:

The function that gives the height in feet of the ball t seconds after it is thrown is :


h(t)=-16t^2+48t+160

We need to find how long will it be before the ball hits the ground. When it hits the ground, its height will be equal to 0.

So,


-16t^2+48t+160=0

We need to solve this equation. When we solve, we get its solution as shown in the figure. We can see that t = -2 s and t = 5 s.

t = -2 s is not possible.

Hence, the ball will hit the ground before 5 seconds.

A ball is thrown from the top row of seats in a stadium. The function h(t)=-16t2+48t-example-1
User DeeveeABC
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