Question

In the given figure, ABCD is a trapezium in which AD || BC,

ABC = 90°, AD = 16 cm, AC = 41 cm and BC = 40 cm. Find the
area of the trapezium,
​

Answer 1

252 cm²

Explanation:

Find AB:

AB² = 41² - 40²

AB² = 81

AB = √81

AB = 9 cm

Area of the trapezium = ½(a + b) × h

Where,

a = 16 cm

b = 40 cm

h = 9 cm

Area = ½(16 + 40) × 9

Area = ½(56)×9

Area = 252 cm²